A、”Nine mainstream schools of the ten schools of thought.”
B、“Contention of a hundred schools of thought”
C、”A Hundred Schools of Thought”
D、“A Hundred Flowers Blossom”
喵查答案：“A Hundred Schools of Thought”
During the period from the late Spring and Autumn Period to the early Han Dynasty, various schools of thought and their proponents. Later generations referred to the large number of scholars and their works which had emerged at that time as ___________(numerous philosophers and their works), and classified them into ten schools of thought: Confucianism, Mohism, Daoism, Logicians, Legalism, School of Yin-Yang, Agriculturalism, School of Diplomacy, Syncretism (or School of Miscellany, za jia), and School of Minor Talks (xiaoshuo jia).
-
Mongolian Beef is recognized and beloved in American Chinese cuisine for its bold flavors, consisting of tender beef strips stir-fried with scallions and a rich, savory sauce. -
Chicken Shaslick is indeed considered a favorite Chinese dish in Pakistan, known for its saucy chicken and vegetables with tangy sauce. -
Wontons, a type of Chinese dumpling, are popular in Pakistan and are made with square wrappers filled with various ingredients. -
Sweet and Sour Pork is a widely ordered dish in Chinese restaurants across the United States, known for its combination of crispy pork pieces in a tangy and sweet sauce.
- 定义如下变量和数组： int k; int a[3][3]={1,2,3,4,5,6,7,8,9}; 则下面语句的输出结果是________。 for(k=0;k<3;k++) printf("%d ",a[k][2-k]);
- 下面程序的运行结果是________int main(){ int a[6],i; for(i=1;i3))%5; printf(“%2d”,a[i]); } return 0;}
- 定义如下的变量和数组int i;int y[2][3]={2,4,6,8,10,12}则下面语句输出结果for(i=0;i<2;i++)printf("%d ",y[1-i][i+1]);
- 以下程序段给数组所有的元素的输入数据，请选择正确的答案#includemain(){float x[5],m=0;while(m<5)scanf(“%.2f”,______);}
- 要求下面的程序运行后，显示如下结果：2 10 4 61 5 2 32 4 7 85 1 3 2则程序中的划线处应填入________.#include void main( ){ int a[4][4]={ ________ }; int i,j; for(i=0;i<4;i++) {for(j=0;j<4;j++) printf("%4d",a[i][j]); printf("\n"); }
- 执行下面的程序段后,变量a中的值为int a=3, s[5]={1};s[0]=a; a=s[2]*10;
- 执行下面的程序段后,变量a中的值为int a=3, s[5]={1,2};s[0]=a; a=s[2]*10;
- 下列程序执行后的输出结果是int a[3][3]={1,2,3,4,5,6,7,8,9};printf(“%d \n”,a[1][2]);