A、The “type field” specified in the 802.3 corresponds to the “type/length field” of Ethernet V2.0 frames
B、No length field is set in DIX frames, and the receiving end can only determine the receiving state of a frame based on the interval between them
C、The minimum length of the data field is 64B and the maximum length is 1500B
D、The destination address of all 1 is the broadcast address, and the frame will be received by all nodes
喵查答案：The minimum length of the data field is 64B and the maximum length is 1500B
Which is wrong among the following descriptions of the frame structure of Ethernet
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Generally speaking, the higher the sound quality is required, the higher the quantization level and the lower the sampling frequency is. -
The higher the sampling frequency, the closer the discrete digitized sound wave is to its original waveform. -
Audio files in WAV format do not use compression algorithm, so they have good sound restorability, strong stereoscopic impression and relatively large file capacity. -
MPEG video compression standards include MPEG-1, MPEG-2, MPEG-4, MPEG-7 and MPEG-21.
- 定义如下变量和数组： int k; int a[3][3]={1,2,3,4,5,6,7,8,9}; 则下面语句的输出结果是________。 for(k=0;k<3;k++) printf("%d ",a[k][2-k]);
- 下面程序的运行结果是________int main(){ int a[6],i; for(i=1;i3))%5; printf(“%2d”,a[i]); } return 0;}
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- 以下程序段给数组所有的元素的输入数据，请选择正确的答案#includemain(){float x[5],m=0;while(m<5)scanf(“%.2f”,______);}
- 要求下面的程序运行后，显示如下结果：2 10 4 61 5 2 32 4 7 85 1 3 2则程序中的划线处应填入________.#include void main( ){ int a[4][4]={ ________ }; int i,j; for(i=0;i<4;i++) {for(j=0;j<4;j++) printf("%4d",a[i][j]); printf("\n"); }
- 执行下面的程序段后,变量a中的值为int a=3, s[5]={1};s[0]=a; a=s[2]*10;
- 执行下面的程序段后,变量a中的值为int a=3, s[5]={1,2};s[0]=a; a=s[2]*10;
- 下列程序执行后的输出结果是int a[3][3]={1,2,3,4,5,6,7,8,9};printf(“%d \n”,a[1][2]);