喵查铺子
MOOC答案
学习通答案
智慧树答案
超星尔雅答案
热门题目
游戏推荐
编程杂谈
AI人工智能学习
flutter开发
登录
注册
用户名或电子邮箱地址
密码
记住我
快乐学习 一个网站喵查铺子(catpuzi.com)全搞定~
>
中国大学MOOC答案
>
The commonly used methods of frame synchronization are character counting method, delimiter method with byte filling, delimiter mark method with bit filling and physical layer coding violation method.
The commonly used methods of frame synchronization are character counting method, delimiter method with byte filling, delimiter mark method with bit filling and physical layer coding violation method.
中国大学MOOC答案
数据帝
2024-04-09
-->
A、正确
B、错误
喵查答案:
正确
喜欢 (
0
)
CRC verification cannot absolutely ensure the correct verification of data.
In data frames, when control characters appear in the transmitted data, appropriate measures must be taken so that the receiving party does not mistake the data for control information. This ensures that the data link layer is connection-oriented.
关于作者:
数据帝
作者主页
Generally speaking, the higher the sound quality is required, the higher the quantization level and the lower the sampling frequency is.
The higher the sampling frequency, the closer the discrete digitized sound wave is to its original waveform.
Audio files in WAV format do not use compression algorithm, so they have good sound restorability, strong stereoscopic impression and relatively large file capacity.
MPEG video compression standards include MPEG-1, MPEG-2, MPEG-4, MPEG-7 and MPEG-21.
定义如下变量和数组: int k; int a[3][3]={1,2,3,4,5,6,7,8,9}; 则下面语句的输出结果是________。 for(k=0;k<3;k++) printf("%d ",a[k][2-k]);
下面程序的运行结果是________int main(){ int a[6],i; for(i=1;i3))%5; printf(“%2d”,a[i]); } return 0;}
定义如下的变量和数组int i;int y[2][3]={2,4,6,8,10,12}则下面语句输出结果for(i=0;i<2;i++)printf("%d ",y[1-i][i+1]);
以下程序段给数组所有的元素的输入数据,请选择正确的答案#includemain(){float x[5],m=0;while(m<5)scanf(“%.2f”,______);}
要求下面的程序运行后,显示如下结果:2 10 4 61 5 2 32 4 7 85 1 3 2则程序中的划线处应填入________.#include void main( ){ int a[4][4]={ ________ }; int i,j; for(i=0;i<4;i++) {for(j=0;j<4;j++) printf("%4d",a[i][j]); printf("\n"); }
执行下面的程序段后,变量a中的值为int a=3, s[5]={1};s[0]=a; a=s[2]*10;
执行下面的程序段后,变量a中的值为int a=3, s[5]={1,2};s[0]=a; a=s[2]*10;
下列程序执行后的输出结果是int a[3][3]={1,2,3,4,5,6,7,8,9};printf(“%d \n”,a[1][2]);